-4(3v-4)+2v=6(v+3)

Solution for -4(3v-4)+2v=6(v+3) equation:

-4(3v-4)+2v=6(v+3)

We move all terms to the left:

-4(3v-4)+2v-(6(v+3))=0

We add all the numbers together, and all the variables

2v-4(3v-4)-(6(v+3))=0

We multiply parentheses

2v-12v-(6(v+3))+16=0


We calculate terms in parentheses: -(6(v+3)), so:

6(v+3)

We multiply parentheses

6v+18

Back to the equation:

-(6v+18)


We add all the numbers together, and all the variables

-10v-(6v+18)+16=0

We get rid of parentheses

-10v-6v-18+16=0

We add all the numbers together, and all the variables

-16v-2=0

We move all terms containing v to the left, all other terms to the right

-16v=2

v=2/-16

v=-1/8