(10x-1)(3x+2)=0

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Solution for (10x-1)(3x+2)=0 equation:



(10x-1)(3x+2)=0
We multiply parentheses ..
(+30x^2+20x-3x-2)=0
We get rid of parentheses
30x^2+20x-3x-2=0
We add all the numbers together, and all the variables
30x^2+17x-2=0
a = 30; b = 17; c = -2;
Δ = b2-4ac
Δ = 172-4·30·(-2)
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{529}=23$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-23}{2*30}=\frac{-40}{60} =-2/3 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+23}{2*30}=\frac{6}{60} =1/10 $

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