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3(x-2)+4x=10(x+1
We move all terms to the left:
3(x-2)+4x-(10(x+1)=0
We add all the numbers together, and all the variables
4x+3(x-2)-(10(x+1)=0
We multiply parentheses
4x+3x-(10(x+1)-6=0
We add all the numbers together, and all the variables
7x-(10(x+1)-6=0
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