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6z+5=5(2+z)
We move all terms to the left:
6z+5-(5(2+z))=0
We add all the numbers together, and all the variables
6z-(5(z+2))+5=0
We calculate terms in parentheses: -(5(z+2)), so:We get rid of parentheses
5(z+2)
We multiply parentheses
5z+10
Back to the equation:
-(5z+10)
6z-5z-10+5=0
We add all the numbers together, and all the variables
z-5=0
We move all terms containing z to the left, all other terms to the right
z=5
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