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9x-3(2x-4)=2(5-x)+7
We move all terms to the left:
9x-3(2x-4)-(2(5-x)+7)=0
We add all the numbers together, and all the variables
9x-3(2x-4)-(2(-1x+5)+7)=0
We multiply parentheses
9x-6x-(2(-1x+5)+7)+12=0
We calculate terms in parentheses: -(2(-1x+5)+7), so:We add all the numbers together, and all the variables
2(-1x+5)+7
We multiply parentheses
-2x+10+7
We add all the numbers together, and all the variables
-2x+17
Back to the equation:
-(-2x+17)
3x-(-2x+17)+12=0
We get rid of parentheses
3x+2x-17+12=0
We add all the numbers together, and all the variables
5x-5=0
We move all terms containing x to the left, all other terms to the right
5x=5
x=5/5
x=1
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