3(1y+10)=27

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Solution for 3(1y+10)=27 equation: 



3(1y+10)=27

We move all terms to the left:

3(1y+10)-(27)=0

We add all the numbers together, and all the variables

3(y+10)-27=0

We multiply parentheses

3y+30-27=0

We add all the numbers together, and all the variables

3y+3=0

We move all terms containing y to the left, all other terms to the right

3y=-3

y=-3/3

y=-1

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