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2x+2(3x-1)=9(x+2)-10-3x
We move all terms to the left:
2x+2(3x-1)-(9(x+2)-10-3x)=0
We multiply parentheses
2x+6x-(9(x+2)-10-3x)-2=0
We calculate terms in parentheses: -(9(x+2)-10-3x), so:We add all the numbers together, and all the variables
9(x+2)-10-3x
determiningTheFunctionDomain 9(x+2)-3x-10
We add all the numbers together, and all the variables
-3x+9(x+2)-10
We multiply parentheses
-3x+9x+18-10
We add all the numbers together, and all the variables
6x+8
Back to the equation:
-(6x+8)
8x-(6x+8)-2=0
We get rid of parentheses
8x-6x-8-2=0
We add all the numbers together, and all the variables
2x-10=0
We move all terms containing x to the left, all other terms to the right
2x=10
x=10/2
x=5
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