-3(8-y)=6(1/2y-4

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Solution for -3(8-y)=6(1/2y-4 equation: 



-3(8-y)=6(1/2y-4

We move all terms to the left:

-3(8-y)-(6(1/2y-4)=0



Domain of the equation: 2y-4)!=0

y∈R



We add all the numbers together, and all the variables

-3(-1y+8)-(6(1/2y-4)=0

We multiply parentheses

3y-(6(1/2y-4)-24=0

We multiply all the terms by the denominator


3y*2y-4)-24-(6(1=0

We add all the numbers together, and all the variables

3y*2y=0

Wy multiply elements

6y^2=0

a = 6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·6·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{12}=0$

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