3v+3(2v-6)=7v+(v+3)

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Solution for 3v+3(2v-6)=7v+(v+3) equation: 



3v+3(2v-6)=7v+(v+3)

We move all terms to the left:

3v+3(2v-6)-(7v+(v+3))=0

We multiply parentheses

3v+6v-(7v+(v+3))-18=0



We calculate terms in parentheses: -(7v+(v+3)), so:

7v+(v+3)

We get rid of parentheses

7v+v+3

We add all the numbers together, and all the variables

8v+3

Back to the equation:

-(8v+3)



We add all the numbers together, and all the variables

9v-(8v+3)-18=0

We get rid of parentheses

9v-8v-3-18=0

We add all the numbers together, and all the variables

v-21=0

We move all terms containing v to the left, all other terms to the right

v=21

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