1/7z+8=12

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Solution for 1/7z+8=12 equation: 



1/7z+8=12

We move all terms to the left:

1/7z+8-(12)=0



Domain of the equation: 7z!=0

z!=0/7

z!=0

z∈R



We add all the numbers together, and all the variables

1/7z-4=0

We multiply all the terms by the denominator


-4*7z+1=0

Wy multiply elements

-28z+1=0

We move all terms containing z to the left, all other terms to the right

-28z=-1

z=-1/-28

z=1/28

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