3v+3(2v-6)=7+4(v+3)

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Solution for 3v+3(2v-6)=7+4(v+3) equation:



3v+3(2v-6)=7+4(v+3)
We move all terms to the left:
3v+3(2v-6)-(7+4(v+3))=0
We multiply parentheses
3v+6v-(7+4(v+3))-18=0
We calculate terms in parentheses: -(7+4(v+3)), so:
7+4(v+3)
determiningTheFunctionDomain 4(v+3)+7
We multiply parentheses
4v+12+7
We add all the numbers together, and all the variables
4v+19
Back to the equation:
-(4v+19)
We add all the numbers together, and all the variables
9v-(4v+19)-18=0
We get rid of parentheses
9v-4v-19-18=0
We add all the numbers together, and all the variables
5v-37=0
We move all terms containing v to the left, all other terms to the right
5v=37
v=37/5
v=7+2/5

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