X+1/5=1/4(20x-24)

Solution for X+1/5=1/4(20x-24) equation:

X+1/5=1/4(20X-24)

We move all terms to the left:

X+1/5-(1/4(20X-24))=0


Domain of the equation: 4(20X-24))!=0

X∈R


We calculate fractions


X+()/400X+(4X2/400X=0

We multiply all the terms by the denominator


X*400X+(4X2+()=0


We calculate terms in parentheses: +(4X2+(), so:

4X2+(

We add all the numbers together, and all the variables

4X^2

Back to the equation:

+(4X^2)


determiningTheFunctionDomain
4X^2+X*400X=0

Wy multiply elements

4X^2+400X^2=0

We add all the numbers together, and all the variables

404X^2=0

a = 404; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·404·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$X=\frac{-b}{2a}=\frac{0}{808}=0$