k(9k-2)=0

Solution for k(9k-2)=0 equation:

k(9k-2)=0

We multiply parentheses

9k^2-2k=0

a = 9; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·9·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*9}=\frac{0}{18}
=0
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*9}=\frac{4}{18}
=2/9
$