(8h-9)(h-3)=0

Solution for (8h-9)(h-3)=0 equation:

(8h-9)(h-3)=0

We multiply parentheses ..

(+8h^2-24h-9h+27)=0

We get rid of parentheses

8h^2-24h-9h+27=0

We add all the numbers together, and all the variables

8h^2-33h+27=0

a = 8; b = -33; c = +27;
Δ = b2-4ac
Δ = -332-4·8·27
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-33)-15}{2*8}=\frac{18}{16}
=1+1/8
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-33)+15}{2*8}=\frac{48}{16}
=3
$