(x+2)=x2+6x+8

Solution for (x+2)=x2+6x+8 equation:

(x+2)=x2+6x+8

We move all terms to the left:

(x+2)-(x2+6x+8)=0

We add all the numbers together, and all the variables

-(+x^2+6x+8)+(x+2)=0

We get rid of parentheses

-x^2-6x+x-8+2=0

We add all the numbers together, and all the variables

-1x^2-5x-6=0

a = -1; b = -5; c = -6;
Δ = b2-4ac
Δ = -52-4·(-1)·(-6)
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-1}{2*-1}=\frac{4}{-2}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+1}{2*-1}=\frac{6}{-2}
=-3
$