x=0.8+0.2(-18.4/3)

Solution for x=0.8+0.2(-18.4/3) equation:

x=0.8+0.2(-18.4/3)

We move all terms to the left:

x-(0.8+0.2(-18.4/3))=0

We multiply all the terms by the denominator


x*3))-(0.8+0.2(-18.4=0

Wy multiply elements

3x^2-18.4=0

a = 3; b = 0; c = -18.4;
Δ = b2-4ac
Δ = 02-4·3·(-18.4)
Δ = 220.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{220.8}}{2*3}=\frac{0-\sqrt{220.8}}{6}
=-\frac{\sqrt{}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{220.8}}{2*3}=\frac{0+\sqrt{220.8}}{6}
=\frac{\sqrt{}}{6}
$