X(3x-8)=(3x+5)(x-4)

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Solution for X(3x-8)=(3x+5)(x-4) equation: 



X(3X-8)=(3X+5)(X-4)

We move all terms to the left:

X(3X-8)-((3X+5)(X-4))=0

We multiply parentheses

3X^2-8X-((3X+5)(X-4))=0

We multiply parentheses ..

3X^2-((+3X^2-12X+5X-20))-8X=0



We calculate terms in parentheses: -((+3X^2-12X+5X-20)), so:

(+3X^2-12X+5X-20)

We get rid of parentheses

3X^2-12X+5X-20

We add all the numbers together, and all the variables

3X^2-7X-20

Back to the equation:

-(3X^2-7X-20)



We add all the numbers together, and all the variables

3X^2-8X-(3X^2-7X-20)=0

We get rid of parentheses

3X^2-3X^2-8X+7X+20=0

We add all the numbers together, and all the variables

-1X+20=0

We move all terms containing X to the left, all other terms to the right

-X=-20

X=-20/-1

X=+20

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