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1/2t+1/4t=5
We move all terms to the left:
1/2t+1/4t-(5)=0
Domain of the equation: 2t!=0
t!=0/2
t!=0
t∈R
Domain of the equation: 4t!=0We calculate fractions
t!=0/4
t!=0
t∈R
4t/8t^2+2t/8t^2-5=0
We multiply all the terms by the denominator
4t+2t-5*8t^2=0
We add all the numbers together, and all the variables
6t-5*8t^2=0
Wy multiply elements
-40t^2+6t=0
a = -40; b = 6; c = 0;
Δ = b2-4ac
Δ = 62-4·(-40)·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6}{2*-40}=\frac{-12}{-80} =3/20 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6}{2*-40}=\frac{0}{-80} =0 $
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