5/x=3/2x+1

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Solution for 5/x=3/2x+1 equation:



5/x=3/2x+1
We move all terms to the left:
5/x-(3/2x+1)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 2x+1)!=0
x∈R
We get rid of parentheses
5/x-3/2x-1=0
We calculate fractions
10x/2x^2+(-3x)/2x^2-1=0
We multiply all the terms by the denominator
10x+(-3x)-1*2x^2=0
Wy multiply elements
-2x^2+10x+(-3x)=0
We get rid of parentheses
-2x^2+10x-3x=0
We add all the numbers together, and all the variables
-2x^2+7x=0
a = -2; b = 7; c = 0;
Δ = b2-4ac
Δ = 72-4·(-2)·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-7}{2*-2}=\frac{-14}{-4} =3+1/2 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+7}{2*-2}=\frac{0}{-4} =0 $

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