(4x-1)(x-4)=(3x+2)(x-7)

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Solution for (4x-1)(x-4)=(3x+2)(x-7) equation: 



(4x-1)(x-4)=(3x+2)(x-7)

We move all terms to the left:

(4x-1)(x-4)-((3x+2)(x-7))=0

We multiply parentheses ..

(+4x^2-16x-1x+4)-((3x+2)(x-7))=0



We calculate terms in parentheses: -((3x+2)(x-7)), so:

(3x+2)(x-7)

We multiply parentheses ..

(+3x^2-21x+2x-14)

We get rid of parentheses

3x^2-21x+2x-14

We add all the numbers together, and all the variables

3x^2-19x-14

Back to the equation:

-(3x^2-19x-14)



We get rid of parentheses

4x^2-3x^2-16x-1x+19x+4+14=0

We add all the numbers together, and all the variables

x^2+2x+18=0

a = 1; b = 2; c = +18;
Δ = b2-4ac
Δ = 22-4·1·18
Δ = -68
Delta is less than zero, so there is no solution for the equation

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