41=4(5x+5)+1

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Solution for 41=4(5x+5)+1 equation: 



41=4(5x+5)+1

We move all terms to the left:

41-(4(5x+5)+1)=0



We calculate terms in parentheses: -(4(5x+5)+1), so:

4(5x+5)+1

We multiply parentheses

20x+20+1

We add all the numbers together, and all the variables

20x+21

Back to the equation:

-(20x+21)



We get rid of parentheses

-20x-21+41=0

We add all the numbers together, and all the variables

-20x+20=0

We move all terms containing x to the left, all other terms to the right

-20x=-20

x=-20/-20

x=1

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