17x+3(2x-3)=3(x-5)+106

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Solution for 17x+3(2x-3)=3(x-5)+106 equation: 



17x+3(2x-3)=3(x-5)+106

We move all terms to the left:

17x+3(2x-3)-(3(x-5)+106)=0

We multiply parentheses

17x+6x-(3(x-5)+106)-9=0



We calculate terms in parentheses: -(3(x-5)+106), so:

3(x-5)+106

We multiply parentheses

3x-15+106

We add all the numbers together, and all the variables

3x+91

Back to the equation:

-(3x+91)



We add all the numbers together, and all the variables

23x-(3x+91)-9=0

We get rid of parentheses

23x-3x-91-9=0

We add all the numbers together, and all the variables

20x-100=0

We move all terms containing x to the left, all other terms to the right

20x=100

x=100/20

x=5

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