19(2x-3)+3(x-2)=3(2x-13)+11

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Solution for 19(2x-3)+3(x-2)=3(2x-13)+11 equation:



19(2x-3)+3(x-2)=3(2x-13)+11
We move all terms to the left:
19(2x-3)+3(x-2)-(3(2x-13)+11)=0
We multiply parentheses
38x+3x-(3(2x-13)+11)-57-6=0
We calculate terms in parentheses: -(3(2x-13)+11), so:
3(2x-13)+11
We multiply parentheses
6x-39+11
We add all the numbers together, and all the variables
6x-28
Back to the equation:
-(6x-28)
We add all the numbers together, and all the variables
41x-(6x-28)-63=0
We get rid of parentheses
41x-6x+28-63=0
We add all the numbers together, and all the variables
35x-35=0
We move all terms containing x to the left, all other terms to the right
35x=35
x=35/35
x=1

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