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X(X+15)=18
We move all terms to the left:
X(X+15)-(18)=0
We multiply parentheses
X^2+15X-18=0
a = 1; b = 15; c = -18;
Δ = b2-4ac
Δ = 152-4·1·(-18)
Δ = 297
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{297}=\sqrt{9*33}=\sqrt{9}*\sqrt{33}=3\sqrt{33}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-3\sqrt{33}}{2*1}=\frac{-15-3\sqrt{33}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+3\sqrt{33}}{2*1}=\frac{-15+3\sqrt{33}}{2} $
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