(2c+4)=(5c+5)-7

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Solution for (2c+4)=(5c+5)-7 equation: 



(2c+4)=(5c+5)-7

We move all terms to the left:

(2c+4)-((5c+5)-7)=0

We get rid of parentheses

2c-((5c+5)-7)+4=0



We calculate terms in parentheses: -((5c+5)-7), so:

(5c+5)-7

We get rid of parentheses

5c+5-7

We add all the numbers together, and all the variables

5c-2

Back to the equation:

-(5c-2)



We get rid of parentheses

2c-5c+2+4=0

We add all the numbers together, and all the variables

-3c+6=0

We move all terms containing c to the left, all other terms to the right

-3c=-6

c=-6/-3

c=+2

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