-7/2y+7/5=-3/5y-1

Solution for -7/2y+7/5=-3/5y-1 equation:

-7/2y+7/5=-3/5y-1

We move all terms to the left:

-7/2y+7/5-(-3/5y-1)=0


Domain of the equation: 2y!=0

y!=0/2

y!=0

y∈R



Domain of the equation: 5y-1)!=0

y∈R


We get rid of parentheses

-7/2y+3/5y+1+7/5=0

We calculate fractions


(-875y)/250y^2+6y/250y^2+14y/250y^2+1=0

We multiply all the terms by the denominator


(-875y)+6y+14y+1*250y^2=0

We add all the numbers together, and all the variables

20y+(-875y)+1*250y^2=0

Wy multiply elements

250y^2+20y+(-875y)=0

We get rid of parentheses

250y^2+20y-875y=0

We add all the numbers together, and all the variables

250y^2-855y=0

a = 250; b = -855; c = 0;
Δ = b2-4ac
Δ = -8552-4·250·0
Δ = 731025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{731025}=855$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-855)-855}{2*250}=\frac{0}{500}
=0
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-855)+855}{2*250}=\frac{1710}{500}
=3+21/50
$