0=6(b+3)+6(b+7)

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Solution for 0=6(b+3)+6(b+7) equation: 



0=6(b+3)+6(b+7)

We move all terms to the left:

0-(6(b+3)+6(b+7))=0

We add all the numbers together, and all the variables

-(6(b+3)+6(b+7))=0



We calculate terms in parentheses: -(6(b+3)+6(b+7)), so:

6(b+3)+6(b+7)

We multiply parentheses

6b+6b+18+42

We add all the numbers together, and all the variables

12b+60

Back to the equation:

-(12b+60)



We get rid of parentheses

-12b-60=0

We move all terms containing b to the left, all other terms to the right

-12b=60

b=60/-12

b=-5

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