2y+1-2(-6y-5)=4(y-1)

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Solution for 2y+1-2(-6y-5)=4(y-1) equation: 



2y+1-2(-6y-5)=4(y-1)

We move all terms to the left:

2y+1-2(-6y-5)-(4(y-1))=0

We multiply parentheses

2y+12y-(4(y-1))+10+1=0



We calculate terms in parentheses: -(4(y-1)), so:

4(y-1)

We multiply parentheses

4y-4

Back to the equation:

-(4y-4)



We add all the numbers together, and all the variables

14y-(4y-4)+11=0

We get rid of parentheses

14y-4y+4+11=0

We add all the numbers together, and all the variables

10y+15=0

We move all terms containing y to the left, all other terms to the right

10y=-15

y=-15/10

y=-1+1/2

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