6(y+4)=-2(8y-7)+14y

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Solution for 6(y+4)=-2(8y-7)+14y equation: 



6(y+4)=-2(8y-7)+14y

We move all terms to the left:

6(y+4)-(-2(8y-7)+14y)=0

We multiply parentheses

6y-(-2(8y-7)+14y)+24=0



We calculate terms in parentheses: -(-2(8y-7)+14y), so:

-2(8y-7)+14y

We add all the numbers together, and all the variables

14y-2(8y-7)

We multiply parentheses

14y-16y+14

We add all the numbers together, and all the variables

-2y+14

Back to the equation:

-(-2y+14)



We get rid of parentheses

6y+2y-14+24=0

We add all the numbers together, and all the variables

8y+10=0

We move all terms containing y to the left, all other terms to the right

8y=-10

y=-10/8

y=-1+1/4

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