-3(v+4)=9v-6+2(2v+1)

Solution for -3(v+4)=9v-6+2(2v+1) equation:

-3(v+4)=9v-6+2(2v+1)

We move all terms to the left:

-3(v+4)-(9v-6+2(2v+1))=0

We multiply parentheses

-3v-(9v-6+2(2v+1))-12=0


We calculate terms in parentheses: -(9v-6+2(2v+1)), so:

9v-6+2(2v+1)

determiningTheFunctionDomain
9v+2(2v+1)-6

We multiply parentheses

9v+4v+2-6

We add all the numbers together, and all the variables

13v-4

Back to the equation:

-(13v-4)


We get rid of parentheses

-3v-13v+4-12=0

We add all the numbers together, and all the variables

-16v-8=0

We move all terms containing v to the left, all other terms to the right

-16v=8

v=8/-16

v=-1/2