((x/2)+(x-5))=100

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Solution for ((x/2)+(x-5))=100 equation: 



((x/2)+(x-5))=100

We move all terms to the left:

((x/2)+(x-5))-(100)=0



Domain of the equation: 2)+(x-5))!=0

x∈R



We add all the numbers together, and all the variables

((+x/2)+(x-5))-100=0

We multiply all the terms by the denominator


((+x-100*2)+(x-5))=0



We calculate terms in parentheses: +((+x-100*2)+(x-5)), so:

(+x-100*2)+(x-5)

We add all the numbers together, and all the variables

(x-200)+(x-5)

We get rid of parentheses

x+x-200-5

We add all the numbers together, and all the variables

2x-205

Back to the equation:

+(2x-205)



We get rid of parentheses

2x-205=0

We move all terms containing x to the left, all other terms to the right

2x=205

x=205/2

x=102+1/2

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