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X2-2=2X+13
We move all terms to the left:
X2-2-(2X+13)=0
We add all the numbers together, and all the variables
X^2-(2X+13)-2=0
We get rid of parentheses
X^2-2X-13-2=0
We add all the numbers together, and all the variables
X^2-2X-15=0
a = 1; b = -2; c = -15;
Δ = b2-4ac
Δ = -22-4·1·(-15)
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-8}{2*1}=\frac{-6}{2} =-3 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+8}{2*1}=\frac{10}{2} =5 $
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