2(6z-1)=5(z+3)-3

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Solution for 2(6z-1)=5(z+3)-3 equation: 



2(6z-1)=5(z+3)-3

We move all terms to the left:

2(6z-1)-(5(z+3)-3)=0

We multiply parentheses

12z-(5(z+3)-3)-2=0



We calculate terms in parentheses: -(5(z+3)-3), so:

5(z+3)-3

We multiply parentheses

5z+15-3

We add all the numbers together, and all the variables

5z+12

Back to the equation:

-(5z+12)



We get rid of parentheses

12z-5z-12-2=0

We add all the numbers together, and all the variables

7z-14=0

We move all terms containing z to the left, all other terms to the right

7z=14

z=14/7

z=2

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