3(4y-2)=9y+15

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Solution for 3(4y-2)=9y+15 equation: 



3(4y-2)=9y+15

We move all terms to the left:

3(4y-2)-(9y+15)=0

We multiply parentheses

12y-(9y+15)-6=0

We get rid of parentheses

12y-9y-15-6=0

We add all the numbers together, and all the variables

3y-21=0

We move all terms containing y to the left, all other terms to the right

3y=21

y=21/3

y=7

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