3(2c-4)=4(c+1)

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Solution for 3(2c-4)=4(c+1) equation: 



3(2c-4)=4(c+1)

We move all terms to the left:

3(2c-4)-(4(c+1))=0

We multiply parentheses

6c-(4(c+1))-12=0



We calculate terms in parentheses: -(4(c+1)), so:

4(c+1)

We multiply parentheses

4c+4

Back to the equation:

-(4c+4)



We get rid of parentheses

6c-4c-4-12=0

We add all the numbers together, and all the variables

2c-16=0

We move all terms containing c to the left, all other terms to the right

2c=16

c=16/2

c=8

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