A(x)=3(x-5)+2(3x-1)

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Solution for A(x)=3(x-5)+2(3x-1) equation: 



(A)=3(A-5)+2(3A-1)

We move all terms to the left:

(A)-(3(A-5)+2(3A-1))=0



We calculate terms in parentheses: -(3(A-5)+2(3A-1)), so:

3(A-5)+2(3A-1)

We multiply parentheses

3A+6A-15-2

We add all the numbers together, and all the variables

9A-17

Back to the equation:

-(9A-17)



We get rid of parentheses

A-9A+17=0

We add all the numbers together, and all the variables

-8A+17=0

We move all terms containing A to the left, all other terms to the right

-8A=-17

A=-17/-8

A=2+1/8

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