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1/5m+9=(3)
We move all terms to the left:
1/5m+9-((3))=0
Domain of the equation: 5m!=0determiningTheFunctionDomain 1/5m+9-3=0
m!=0/5
m!=0
m∈R
We add all the numbers together, and all the variables
1/5m+6=0
We multiply all the terms by the denominator
6*5m+1=0
Wy multiply elements
30m+1=0
We move all terms containing m to the left, all other terms to the right
30m=-1
m=-1/30
m=-1/30
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