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(3x+3)+(6x+1)=(10x-5)
We move all terms to the left:
(3x+3)+(6x+1)-((10x-5))=0
We get rid of parentheses
3x+6x-((10x-5))+3+1=0
We calculate terms in parentheses: -((10x-5)), so:We add all the numbers together, and all the variables
(10x-5)
We get rid of parentheses
10x-5
Back to the equation:
-(10x-5)
9x-(10x-5)+4=0
We get rid of parentheses
9x-10x+5+4=0
We add all the numbers together, and all the variables
-1x+9=0
We move all terms containing x to the left, all other terms to the right
-x=-9
x=-9/-1
x=+9
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