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2(x-3)=4(3x-4)
We move all terms to the left:
2(x-3)-(4(3x-4))=0
We multiply parentheses
2x-(4(3x-4))-6=0
We calculate terms in parentheses: -(4(3x-4)), so:We get rid of parentheses
4(3x-4)
We multiply parentheses
12x-16
Back to the equation:
-(12x-16)
2x-12x+16-6=0
We add all the numbers together, and all the variables
-10x+10=0
We move all terms containing x to the left, all other terms to the right
-10x=-10
x=-10/-10
x=1
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