(1/y+1)+1/y+2))=2/y+3

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Solution for (1/y+1)+1/y+2))=2/y+3 equation: 



(1/y+1)+1/y+2))=2/y+3

We move all terms to the left:

(1/y+1)+1/y+2))-(2/y+3)=0



Domain of the equation: y+1)!=0

y∈R





Domain of the equation: y!=0

y∈R





Domain of the equation: y+3)!=0

y∈R



We get rid of parentheses

1/y+1/y+2))-(2/y+3)+1=0

We calculate fractions


y/y^2+2)-(2*y)/y^2=0

We add all the numbers together, and all the variables

y/y^2+2y)/y^2+2)-(=0

We calculate fractions

We do not support eypression: y^4

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