1/2(x-5)+5/2=1/4(x-4)

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Solution for 1/2(x-5)+5/2=1/4(x-4) equation: 



1/2(x-5)+5/2=1/4(x-4)

We move all terms to the left:

1/2(x-5)+5/2-(1/4(x-4))=0



Domain of the equation: 2(x-5)!=0

x∈R





Domain of the equation: 4(x-4))!=0

x∈R



We calculate fractions


(4xx/(2(x-5)*4(x-4))*2)+(-(1*2(x-5)*2)/(2(x-5)*4(x-4))*2)+(20xx/(2(x-5)*4(x-4))*2)=0



We calculate terms in parentheses: +(4xx/(2(x-5)*4(x-4))*2), so:

4xx/(2(x-5)*4(x-4))*2

We multiply all the terms by the denominator


4xx

Back to the equation:

+(4xx)





We calculate terms in parentheses: +(-(1*2(x-5)*2)/(2(x-5)*4(x-4))*2), so:

-(1*2(x-5)*2)/(2(x-5)*4(x-4))*2

We multiply all the terms by the denominator


-(1*2(x-5)*2)



We calculate terms in parentheses: -(1*2(x-5)*2), so:

1*2(x-5)*2

Wy multiply elements

4x(x

Back to the equation:

-(4x(x)



Back to the equation:

+(-(4xx)





We calculate terms in parentheses: +(20xx/(2(x-5)*4(x-4))*2), so:

20xx/(2(x-5)*4(x-4))*2

We multiply all the terms by the denominator


20xx

Back to the equation:

+(20xx)

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