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8x^2+7x-13=0
a = 8; b = 7; c = -13;
Δ = b2-4ac
Δ = 72-4·8·(-13)
Δ = 465
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{465}}{2*8}=\frac{-7-\sqrt{465}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{465}}{2*8}=\frac{-7+\sqrt{465}}{16} $
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