5(t-1)+1=2(t+2)-2

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Solution for 5(t-1)+1=2(t+2)-2 equation: 



5(t-1)+1=2(t+2)-2

We move all terms to the left:

5(t-1)+1-(2(t+2)-2)=0

We multiply parentheses

5t-(2(t+2)-2)-5+1=0



We calculate terms in parentheses: -(2(t+2)-2), so:

2(t+2)-2

We multiply parentheses

2t+4-2

We add all the numbers together, and all the variables

2t+2

Back to the equation:

-(2t+2)



We add all the numbers together, and all the variables

5t-(2t+2)-4=0

We get rid of parentheses

5t-2t-2-4=0

We add all the numbers together, and all the variables

3t-6=0

We move all terms containing t to the left, all other terms to the right

3t=6

t=6/3

t=2

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