2(2-y)(3)=3(2-y)

Solution for 2(2-y)(3)=3(2-y) equation:

2(2-y)(3)=3(2-y)

We move all terms to the left:

2(2-y)(3)-(3(2-y))=0

We add all the numbers together, and all the variables

2(-1y+2)3-(3(-1y+2))=0

We multiply parentheses

-6y-(3(-1y+2))+12=0


We calculate terms in parentheses: -(3(-1y+2)), so:

3(-1y+2)

We multiply parentheses

-3y+6

Back to the equation:

-(-3y+6)


We get rid of parentheses

-6y+3y-6+12=0

We add all the numbers together, and all the variables

-3y+6=0

We move all terms containing y to the left, all other terms to the right

-3y=-6

y=-6/-3

y=+2