15/(x+3)=20/(2x+5)

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Solution for 15/(x+3)=20/(2x+5) equation: 



15/(x+3)=20/(2x+5)

We move all terms to the left:

15/(x+3)-(20/(2x+5))=0



Domain of the equation: (x+3)!=0

We move all terms containing x to the left, all other terms to the right

x!=-3

x∈R





Domain of the equation: (2x+5))!=0

x∈R



We calculate fractions


30x/((x+3)*(2x+5)))+(-(20*(x+3))/((x+3)*(2x+5)))=0



We calculate terms in parentheses: -(20*(x+3))/((x+3)*(2x+5))), so:

20*(x+3))/((x+3)*(2x+5))

We multiply all the terms by the denominator


20*(x+3))

We multiply parentheses

20x+

We add all the numbers together, and all the variables

20x

Back to the equation:

-(20x)



We add all the numbers together, and all the variables

-20x+30x/((x+3)*(2x+5)))+(=0

We multiply all the terms by the denominator


-20x*((x+3)*(2x+5)))+(+30x=0

We add all the numbers together, and all the variables

30x-20x*((x+3)*(2x+5)))+(=0

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