5(q+1)+3=3(q-4)+2

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Solution for 5(q+1)+3=3(q-4)+2 equation: 



5(q+1)+3=3(q-4)+2

We move all terms to the left:

5(q+1)+3-(3(q-4)+2)=0

We multiply parentheses

5q-(3(q-4)+2)+5+3=0



We calculate terms in parentheses: -(3(q-4)+2), so:

3(q-4)+2

We multiply parentheses

3q-12+2

We add all the numbers together, and all the variables

3q-10

Back to the equation:

-(3q-10)



We add all the numbers together, and all the variables

5q-(3q-10)+8=0

We get rid of parentheses

5q-3q+10+8=0

We add all the numbers together, and all the variables

2q+18=0

We move all terms containing q to the left, all other terms to the right

2q=-18

q=-18/2

q=-9

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