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8+4=2x(x-1)
We move all terms to the left:
8+4-(2x(x-1))=0
We add all the numbers together, and all the variables
-(2x(x-1))+12=0
We calculate terms in parentheses: -(2x(x-1)), so:We get rid of parentheses
2x(x-1)
We multiply parentheses
2x^2-2x
Back to the equation:
-(2x^2-2x)
-2x^2+2x+12=0
a = -2; b = 2; c = +12;
Δ = b2-4ac
Δ = 22-4·(-2)·12
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-10}{2*-2}=\frac{-12}{-4} =+3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+10}{2*-2}=\frac{8}{-4} =-2 $
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