8(x-2)+1=4x+4(-3+x)

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Solution for 8(x-2)+1=4x+4(-3+x) equation: 



8(x-2)+1=4x+4(-3+x)

We move all terms to the left:

8(x-2)+1-(4x+4(-3+x))=0

We add all the numbers together, and all the variables

8(x-2)-(4x+4(x-3))+1=0

We multiply parentheses

8x-(4x+4(x-3))-16+1=0



We calculate terms in parentheses: -(4x+4(x-3)), so:

4x+4(x-3)

We multiply parentheses

4x+4x-12

We add all the numbers together, and all the variables

8x-12

Back to the equation:

-(8x-12)



We add all the numbers together, and all the variables

8x-(8x-12)-15=0

We get rid of parentheses

8x-8x+12-15=0

We add all the numbers together, and all the variables

-3!=0

There is no solution for this equation

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