5y+2(y-5)=3(y+1)-2

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Solution for 5y+2(y-5)=3(y+1)-2 equation: 



5y+2(y-5)=3(y+1)-2

We move all terms to the left:

5y+2(y-5)-(3(y+1)-2)=0

We multiply parentheses

5y+2y-(3(y+1)-2)-10=0



We calculate terms in parentheses: -(3(y+1)-2), so:

3(y+1)-2

We multiply parentheses

3y+3-2

We add all the numbers together, and all the variables

3y+1

Back to the equation:

-(3y+1)



We add all the numbers together, and all the variables

7y-(3y+1)-10=0

We get rid of parentheses

7y-3y-1-10=0

We add all the numbers together, and all the variables

4y-11=0

We move all terms containing y to the left, all other terms to the right

4y=11

y=11/4

y=2+3/4

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