6(2n+1)=7(4n+7)+3

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Solution for 6(2n+1)=7(4n+7)+3 equation: 



6(2n+1)=7(4n+7)+3

We move all terms to the left:

6(2n+1)-(7(4n+7)+3)=0

We multiply parentheses

12n-(7(4n+7)+3)+6=0



We calculate terms in parentheses: -(7(4n+7)+3), so:

7(4n+7)+3

We multiply parentheses

28n+49+3

We add all the numbers together, and all the variables

28n+52

Back to the equation:

-(28n+52)



We get rid of parentheses

12n-28n-52+6=0

We add all the numbers together, and all the variables

-16n-46=0

We move all terms containing n to the left, all other terms to the right

-16n=46

n=46/-16

n=-2+7/8

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